在長時間的運動下，脂肪會為身體帶來能源，支撐身體肌肉所需。馬拉松全程為42.195km，脂肪所提供的能源協助絕對不可或缺。980Please respect copyright.ＰＥＮＡＮＡL7dLrlXWTm
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在這個前題下，為何為數不少的瘦削運動員都可以足夠應付長距離的馬拉松呢?980Please respect copyright.ＰＥＮＡＮＡFf5FWsXJrS
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（圖2）在此，我們嘗試一下利用數學角度，以卡路里的消耗量探討這一個問題。980Please respect copyright.ＰＥＮＡＮＡCTagS3lWKm
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有研究確認(Ref1,2)，身體消耗的卡路里是與行走總距離有關，而非行走速度。980Please respect copyright.ＰＥＮＡＮＡb7xB9xOih5
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他們最終得出的公式為每1kg行走1km平地就會消耗1卡路里。980Please respect copyright.ＰＥＮＡＮＡ6Pvm7KH05R
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如果我們假設1個70kg的男人跑一場馬拉松，所消耗的總卡路里就會為980Please respect copyright.ＰＥＮＡＮＡOmlilYDxge
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70kg x 42.195km=980Please respect copyright.ＰＥＮＡＮＡTdsftcRgZI
2950kcal980Please respect copyright.ＰＥＮＡＮＡ2IVcCo7lnK
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（圖3）身體的脂肪每克約可以提供9kcal，如果我們用上最極端的例子，負責儲存能源的體脂只佔身體重量2% (正常為10-32%)的話，所提供得到的能源就會是980Please respect copyright.ＰＥＮＡＮＡ7pFRFbgfrg
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70kg x 1000 x 2% x 9980Please respect copyright.ＰＥＮＡＮＡOBHa7SHCoe
=12600 kcal980Please respect copyright.ＰＥＮＡＮＡPiBsOmB1Qr
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而基於每場馬拉松所消耗的卡路里僅為2950kcal關係，12600/2950 = 4.27，單憑身體脂肪所提供的能源，就足以應付4場馬拉松!980Please respect copyright.ＰＥＮＡＮＡnv5t4Pc1tk
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這個跑4次馬拉松的結果是以極低（儲存能量用的體脂2%）這個極端例子作計算，可以推算得到正常人的話絕對是遊刃有餘跑1場馬拉松；980Please respect copyright.ＰＥＮＡＮＡF1aLmR1iHO
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此計算方式是假設整場馬拉松是平地鋪設，沒有高低鈄坡。980Please respect copyright.ＰＥＮＡＮＡpm934uV4WK
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（圖4）不過，魔鬼在細節，這集反應熱烈的話，下一集將會探討這個計算方式的漏洞以及馬拉松選手經常會遇到所謂Hit The Wall的問題。980Please respect copyright.ＰＥＮＡＮＡ8TusyaCeOn
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如果想我快啲出文的話，請入去Penana網站科普專欄–薯不揀單俾一個like以及Bookmark，這對我非常之重要。980Please respect copyright.ＰＥＮＡＮＡuoXYmovjZm
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Link: https://www.penana.com/story/66244/%E7%A7%91%E6%99%AE%E5%B0%88%E6%AC%84-%E8%96%AF%E4%B8%8D%E6%8F%80%E5%96%AE/toc980Please respect copyright.ＰＥＮＡＮＡfhiUZWG9mQ
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同時亦可以在Penana網站裡按「買一嚿/半嚿薯仔」，以課金的方式推動我繼續搜羅資料寫文，多謝。980Please respect copyright.ＰＥＮＡＮＡZ30RjDa7o2
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Link:980Please respect copyright.ＰＥＮＡＮＡzLg39NmHDS
https://www.penana.com/user/27349/%E8%96%AF%E4%BB%94%E8%81%9E%E8%8C%B1%E8%8E%89/portfolio980Please respect copyright.ＰＥＮＡＮＡAMd5BOkOb4
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有興趣接收科學資訊的話，歡迎follow IG: potatopigtongue。980Please respect copyright.ＰＥＮＡＮＡqDBLQkqkOI
https://www.instagram.com/potatopigtongue/980Please respect copyright.ＰＥＮＡＮＡMkUxFPJ7dn
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Ref1:https://journals.physiology.org/doi/abs/10.1152/jappl.1963.18.2.367980Please respect copyright.ＰＥＮＡＮＡ0GW21DcvlR
Ref2:https://www.ncbi.nlm.nih.gov/pmc/articles/PMC1859586/980Please respect copyright.ＰＥＮＡＮＡ8LLT6DIQy8
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